Introduction of geometrical properties:
The geometry is defined as the main division of the mathematics which is used to represents the basic concepts, relationship, solid measurement, lines, angles and surface area. The geometry also used to include the magnitude concepts and relationships. In the science, geometry used to relate the space. The geometry has basic properties which are explained as following terms.
The geometrical properties are given as follow
Rectangle Perimeter = l + l + w + w = 2 × l + 2 × w = 2+2w
Area of the Rectangle = l × w
Square formula :
Perimeter of the square = c + c + c + c = 4 × c = 4c
Area of the square = c* c = c2
Perimeter of the Parallelogram= c + c + d + d = 2 × c + 2 × d = 2c + 2d
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Area of the Parallelogram = b × h
Perimeter of the Rhombus = c + c + c + c = 4 × c = 4c
Area of the Rhombus = b × h
Perimeter of the Triangle = c + d + e
Area of the Triangle =` (bxxh)/2`
Perimeter of the Trapezoid = c +d + e + f
Area of the Trapezoid = `((c+d) * h) / 2`
Perimeter of Circle = 2 × `pi` × R or Perimeter = `pi` × d
Area of the Circle =` pi` × R2 or Area = `(pi xx d^2)/4`
Geometrical Properties with its Problems:
The geometrical properties and its problems are given asfollow:
Find the area and perimeter of square when side length is 2 cm?
Area of square = (side*side)
=> 4 cm2
Perimeter of square= 4* side
= 8 cm
Find the area and perimeter of rectangle with length 3 cm,width 10 cm?
Area of rectangle = Length x width
= 30 cm2
Perimeter of rectangle= 2(Length +width)
= 2 (3+10)
= 60 cm
Find the area and perimeter of triangle Base= 1 cm , Height= 4 cm, other two sides are 5,7?
= 2 cm2
Perimeter= (sum of three sides)
= 13 cm
The geometrical properties with its practice problems:
1.Calculate the area of the square the side length is 6 cm?
Solution: Area of the square is 36 cm2
2. Calculate the area of the trianglen the base and height of the triangle is 3 cm and 5 cm?
Solution: Area of the triangle is 4 cm2.